Barenboim M, Chang C Y, dib Hajj F, Young R
Department of Biology, Texas A&M University, College Station, TX 77843, USA.
Mol Microbiol. 1999 May;32(4):715-27. doi: 10.1046/j.1365-2958.1999.01385.x.
Holins are small membrane proteins that, at a genetically programmed time in a bacteriophage infective cycle, allow bacteriolytic enzymes, or endolysins, to escape to the periplasm and to attack the cell wall. Most holins fall into two sequence classes, I and II, based on the number of potential transmembrane domains (three for class I and two for class II). The prototype class I holin gene, S lambda, has a dual start motif and encodes not only the effector holin, Slambda105, but also an inhibitor, Slambda107, with a Met-Lys ...extension at the terminus. The prototype class II holin gene of phage 21, S 21, begins with the motif Met-Lys-Ser-Met ..., and a potential RNA secondary structure overlaps the Shine-Dalgarno sequence. Here, we demonstrate that (i) two protein products are elaborated from S 21, S2171 and S2168; (ii) the shorter product is required for lysis; (iii) the longer product, S2171, inhibits S 21 function; and (iv) the Lys-2 residue is important for the inhibitor function. Moreover, the RNA stem-loop structure is involved in the downregulation of S2171 synthesis. However, our results suggest that, in S 21, different segments of the single consensus Shine-Dalgarno sequence serve the two translational starts. These results show that the dual start motifs of class II holin genes are functionally homologous to those of class I holin genes.
穿孔素是一种小的膜蛋白,在噬菌体感染周期的特定基因编程时间,它能使溶菌酶或内溶素释放到周质空间并攻击细胞壁。根据潜在跨膜结构域的数量,大多数穿孔素可分为I和II两类序列(I类有三个,II类有两个)。I类穿孔素基因的原型S lambda具有双重起始基序,不仅编码效应穿孔素Slambda105,还编码一种抑制剂Slambda107,其末端有一个Met-Lys...延伸序列。噬菌体21的II类穿孔素基因原型S 21,起始基序为Met-Lys-Ser-Met...,一个潜在的RNA二级结构与Shine-Dalgarno序列重叠。在此,我们证明:(i)从S 21产生了两种蛋白质产物S2171和S2168;(ii)裂解需要较短的产物;(iii)较长的产物S2171抑制S 21的功能;(iv)Lys-2残基对抑制剂功能很重要。此外,RNA茎环结构参与了S2171合成的下调。然而,我们的结果表明,在S 21中,单一共有Shine-Dalgarno序列的不同片段用于两个翻译起始。这些结果表明,II类穿孔素基因的双重起始基序在功能上与I类穿孔素基因的双重起始基序同源。